Is there a way to search and replace a regular expression in Google Docs spreadsheets?

Question

The problem is that I entered a lot of formulas like =round(x+y) into a Google Docs spreadsheet. Now I need them exported to MS Excel and the latter only accepts =round(x+y,0) as a valid format. Since the doc holds a few 10s of this format - any suggestion on how to convert these would be highly appreciated (like if it can be done in MS Excel that's OK as well).

What I was thinking was a awk script sort of thing: find all round(*) replace with round(*,0)... of course this will have to ignore all the round(*,2) that I also have.

Tried to use the find and replace menu but it doesn't find round at all (and believe me it is there).

Answer 1

You can find them using find and replace if you go to view -> all formulas (ctrl+') and then do you "round( " find this will at least cut down on the manual labor of it all

I couldnt find a way (using find and replace to search for wild card value though

EDIT:

Try out the script below REF: http://www.google.com/support/forum/p/Google%20Docs/thread?tid=288d77c8c9ad7696&hl=en

function SearchReplaceInFormula() {

  var pattern = Browser.inputBox("Enter the search string:");
  var replacement = Browser.inputBox("Enter the replacement string:");
  if (pattern == "" && replacement == "")
  {
    Browser.msgBox("Nothing to search and or replace");
    return;
  }

  var formula = SpreadsheetApp.getActiveRange().getFormulaR1C1();
  var range = SpreadsheetApp.getActiveRange();
  var crows = range.getNumRows();
  var ccols = range.getNumColumns();

  var row = 0;
  for (row = 1; row <= crows; row++)
  {
       for (col=1; col <= ccols; col++)
       {
         var cell = range.getCell(row, col);
         var formula = cell.getFormula();
         var updated = formula;
         while(-1 != updated.indexOf(pattern))
         {
           updated = updated.replace(pattern, replacement);
         }
         if (formula != updated)
         {
           cell.setFormula(updated)
         }
       }
  }

  Browser.msgBox("Done replacing " + pattern + " with " + replacement);
}