Take the 2-minute tour ×
Web Applications Stack Exchange is a question and answer site for power users of web applications. It's 100% free, no registration required.

I've been doing some experimentation with If This Then That service.

This service is a web application that allows you to concoct "recipes" between different "channels," e.g., send all my Tweets from Twitter to Facebook (or Google Reader, Evernote, etc.).

Currently, there is a limited number of channels. I'd like to be able to send an alert to another custom application (even a desktop client, perhaps), but such a channel doesn't exist.

Aside from using an existing channel like email or Twitter, and triggering a special email or Tweet as output from IFTTT, with which the custom application could read the result by parsing the email or using the Twitter API, is there a more optimal way to make my own channel to control my custom application directly?

share|improve this question
add comment

1 Answer 1

up vote 1 down vote accepted

How about creating a pipe on Yahoo Pipes? It will allow fine tuning input, output and options. Think of it as your own web service in the cloud, created through simple UI tools.

share|improve this answer
    
I've never used Pipes, I took a look at it, and the concept sounds interesting, but what are Yahoo's long term plans for it? –  jonsca Oct 17 '11 at 9:21
1  
What are Yahoo's long term plans - that's the 6 billion dollar question in the valley right now :) –  Traveling Tech Guy Oct 17 '11 at 16:15
    
Hehe, you know what I mean. I have in the back of my head that they were planning on phasing it out, but perhaps I am thinking of something else. –  jonsca Oct 17 '11 at 19:52
    
You may be thinking of BOSS. MS bought that gig from Yahoo and may be phasing it out in favor of BING –  Traveling Tech Guy Oct 19 '11 at 13:53
add comment

Your Answer

 
discard

By posting your answer, you agree to the privacy policy and terms of service.

Not the answer you're looking for? Browse other questions tagged or ask your own question.