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Could someone tell me how to get WolframAlpha to graph/plot/show graphic of this:

16<=x^2+y^2+z^2<=25 ; x,=0

This did not work:

3dplot[x^2+y^2+z^2]
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This site is really for Mathematica questions. In Mathematica, I think you can use RegionPlot3D, like this: expr = x^2 + y^2 + z^2; RegionPlot3D[ 16 <= x^2 + y^2 + z^2 <= 25, {x, -10, 10}, {y, -10, 10}, {z, -10, 10}] screen shot: !Mathematica graphics (I do not know what x=0 means in your input. –  Nasser Sep 4 '13 at 5:52
    
You might also want post this on community.wolfram.com. –  Yves Klett Sep 4 '13 at 7:03
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But if you do it and get an answer there, please post it here also. –  Alex Sep 4 '13 at 18:35
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migrated from mathematica.stackexchange.com Sep 4 '13 at 6:07

This question came from our site for users of Mathematica.

1 Answer

Manipulate[
 RegionPlot3D[
  16 <= x^2 + y^2 + z^2 <= 25,
  {y, -5, 5}, {z, -5, 5}, {x, -5, xs},
  PlotRange -> {{-5, 5}, {-5, 5}, {-5, 5}},
  AxesLabel -> Automatic],
 {{xs, 0, "x Cross Section"}, -4.5, 5, 0.5,
  Appearance -> "Labeled"}]

Manipulate[
 RegionPlot[
  16 <= x^2 + y^2 + z^2 <= 25,
  {y, -5, 5}, {z, -5, 5},
  PlotRange -> {{-5.5, 5.5}, {-5.5, 5.5}},
  FrameLabel -> Automatic],
 {{x, 0, "x Cross Section"}, -4.5, 4.5, .5,
  Appearance -> "Labeled"}]

I could only get a 2D plot out of WolframAlpha

WolframAlpha[
 "plot 16 <= x^2 + y^2 + z^2 <= 25 with 
 x = 0, y = -5 to 5, z = -5 to 5"]
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Thank you to both of you for your help. –  Joseph Hickman Sep 13 '13 at 4:14
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