Web Applications Stack Exchange is a question and answer site for power users of web applications. Join them; it only takes a minute:

Sign up
Here's how it works:
  1. Anybody can ask a question
  2. Anybody can answer
  3. The best answers are voted up and rise to the top

I am looking for a tool or web application that will automatically tweet new stuff that has just been posted on several blogs. Let's say that on some blog has just appeared new post. That app should tweet about that post from my Twitter account.

Any help?


share|improve this question

migrated from superuser.com Oct 16 '10 at 16:45

This question came from our site for computer enthusiasts and power users.

Depends on who runs the blogs. – BoltClock Oct 16 '10 at 9:51

You can further enhance this sort of automation by combining feeds into one feed using Yahoo Pipes. Simply log in to your Yahoo Account (or sign up if you don't have one), Create A New Pipe, drag the Fetch Feed item (in the sources category) onto the page, specify the RSS feed's URL, click the "+" image to add as many more feeds as you want, then click the round circle at the bottom of the box and drag it to the Pipe Output box to create a merged feed. Once you save it and run it there will be options to Get As RSS. Use that RSS link to feed feedburner.

share|improve this answer

You can se FeedBurner to Tweet new posts.


share|improve this answer
Ok, I assume that if I enter several feeds to this feedburner i have to somehow set up my twitter account to tweet whenever new entry has been posted from this feeds? – Pon Oct 16 '10 at 9:55
No. You add your feeds to FeedBurner (as many as you like). Then under the 'Publicize' tab for each feed is an option to send out a tweet. You put your twitter username in and authenticate with oAuth and it should just work. – Adam Pope Oct 16 '10 at 9:57
YES! Exactly what i was looking for. Thanks a million! – Pon Oct 16 '10 at 10:02

I like using TwitterFeed. You give it an RSS feed, and it will tweet a custom message (such as "New Blog Post:") followed by a link to the need post.

share|improve this answer

Your Answer


By posting your answer, you agree to the privacy policy and terms of service.