The below formula adds a letter after a sequential number, A, B, C, D, etc for the same number until it finds a new number, then it starts again from A.

I need help on turning this into an array formula, if possible?


I tried it this way, and depending on if I amend J3:J3, I get either A or D at end of the number?


The formula as a single line pushes out the below.

enter image description here


 ROW(A2:A)-MATCH(A1:A, A1:A, 0), 4), 1, ))))


  • 1
    Hi User0, thanks, that works a charm. :) – Ceebee86 Jul 17 '19 at 9:05

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