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In Google Sheets I want to be able to copy four rows at a time to a new sheet but every day the four rows change. Each row is 11 cells long.

Example:

Day 1: Rows 1-4

Day 2: Rows 5-8

etc until it hits the bottom and then returns to the top to go again.

My demo sheet https://docs.google.com/spreadsheets/d/1qH1_LplzOaCpiqbN7vTi7ycYK4rWBGPY8dkc3UN7FBA/edit?usp=sharing

  • Welcome. Please read how to and share a test sheet so as you can be easier helped. – marikamitsos May 17 at 3:52
  • Welcome. Parts of your question are unclear or counter-intuitive. Would you please explain i) why is the data to be copied to sheet#2; ii) what will trigger the weekly process; iii) what is the starting point for a week (1st January, another reference date, etc)?; iv) what day of the week is the copy to be made?; v) 336 rows of data, 4 rows/week = 84 weeks. this is 32 weeks longer than a calendar year. is this an intentional deliberate time differential?; vi) until it hits the bottom-a lot of time could be invested to develop a solution for an annual event. is this really necessary? – Tedinoz May 19 at 3:56
  • I made a mistake in my question. I was supposed to say 4 rows per day, not week. I'm trying to setup a webhook to discord that triggers when the 4 rows are updated. It's for a fantasy calendar where 1 day is 4 days in the fantasy world. Sorry if I was unclear. – Silencer May 20 at 2:44
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Try this. Insert this is cell A2 of Sheet2:

=query('Sheet 1'!A2:K337,"Select * limit "& (weeknum(today(),1)*4))

It uses the Limit clause to display four days for each week of the calendar year.

EDIT:
4 days per "day" Try this. Insert this is cell A2 of Sheet2:

=query('Sheet 1'!A2:K337,"Select * limit "& mod(days(today(),date(year(today()),1,1)),84)*4)

This solution also uses the "Limit clause", but the key is in the use of mod to calculate the number of days to display.

  • date(year(today()),1,1) - this returns the starting date in the calendar year. Note the use of year(today()) - this ensures that the starting date will automatically roll over to the start of the following calendar year.
  • days(today(),date(year(today()),1,1)) - this calculates the number of days between "today" and the first day of the calendar year.
  • mod(days(today(),date(year(today()),1,1)),84)- "mod" returns the remainder of a division calculation. In this case, the number of elapsed days is divided by 84. The value of "84" is derived by taking the total number of data-days (336) divided by 4 (display 4 rows per day) - this result is the number of days it takes to get to the bottom of the list. So "mod(days,84)" returns the number of days in the next annual cycle.
  • The solution requires that 4 days of data is displayed for each days of the year. So, the formula multiplies the mod result by 4.
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  • I tried this and it returned the whole Sheet1. – Silencer May 22 at 1:42
  • Are you sure that it returned ALL of sheet 1, or all of the rows down to March 28? Anyway, I have edited the answer to provide a formula to display 4 rows per day as opposed to 4 rows per week. – Tedinoz May 22 at 4:40
  • Thank you very much for working with me. I tried the new formula and it's still filling it with all of Sheet 1. – Silencer May 22 at 21:29
  • Apologies, I have been without internet for a week. A can't explain the response that you are getting. Would you please share a copy of your spreadsheet, excluding private, sensitive or confidential spreadsheet data. When deciding whether to share your spreadsheet, be aware that sharing your spreadsheet will unavoidably expose your email address. – Tedinoz Jun 1 at 23:32
  • @Silencer "I tried the new formula and it's still filling it with all of Sheet 1". I looked at your Test Sheet, and on 6 June 2020 (day#157) the formula fills data to row 293, "November 12". This is the expected result, based on fours days data displayed for every elapsed day of the year. – Tedinoz Jun 6 at 11:59

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