0

So I have two sheets.

Sheet A tab X contains two columns, first one with an url for a google doc and in the other column text IDs.

Sheet B tab Y contains a column with text ID of several more files than Sheet A.

In sheet B i want to import the urls from sheet A in the respective cells in new column matching the text ID.

So urls and text ID matches.

I'm guessing a importrange with query somehow but cant seem to find exactly this issue, any help much appreciated

2

1 Answer 1

0

You need to use a couple of formula to resolve your question. There are many precedents for each element of those formula, but none that combine the specific combination of issues in your scenario.

1 - IMPORTRANGE - this will return a give range from an external spreadsheet. You include this formula in SheetB and import the URL/ID range from SheetA

2 - VLOOKUP - this formula goes in Sheet B, to lookup the ID in Column H in the imported range, and return the URL.

3 - VLOOKUP - range array- Vlookup searches in the first column of a range, but the first column of the imported range is the URL, so we use build an array (using curly brackets {}) to switch the two columns around.

4 - IFERROR - not every ID will have a URL. For those do not, use IFERROR to display an appropriate message.

5 - ARRAYFORMULA - you've got 300+ lines in sheet B, so use ARRAYFORMULA to automatically fill in all the rows from row#5 down to Row 300+

FORMULAS

  • Step#1

Let's assume that you create a new sheet in Spreadsheet B called sheeta. And in Cell A2 of sheeta, you use this formula =importrange("https://docs.google.com/spreadsheets/d/1q6AVzkK0NBCebqz2foJ-Uuj6ovAV1HG7AjRUyw2Qp-o/edit#gid=626967951","Sheet1!A2:B7")

  • Step#2 In SpreadsheetB, Tab Y, use this formula in cell Q6 =ARRAYFORMULA(iferror(VLOOKUP(H6:H322,{sheeta!$B$2:$B$7,sheeta!$A$2:$A$7},2,FALSE),"No URL"))

IMPORTRANGE

importrange

LOOKUP URL

URL


1
  • Thank you so much! worked brilliant! Also thanks for explaining well!
    – Andoriod
    Commented Sep 27, 2021 at 10:59

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.