I'm trying to create a formula that takes a text string of unknown length and returns it after inserting a space between every character.

For example, if A1="FOO" then the formula should return "F O O".

I can successfully return my example above with the following formula, but it's long and is hard-coded for 3 character strings:

=MID(A1,1,1)& " "&
 MID(A1,2,1)& " "&

Is there a more compact method that works with strings of any length?


1 Answer 1


I solved my problem with the following formula:

      A1, "(.)", "$1 "))

Credit to @Erik Tyler for suggesting the TRIM function which provided a much shorter approach to remove trailing spaces.

  • Even though the question is self-answered, you can still accept it and are encouraged to do so after 48 hours if it is the best solution. You can always change your mind later if a better solution comes along.
    – Blindspots
    Sep 21, 2023 at 17:27
  • 1
    Since we seem to share an interest in shortening our code, you can remove an additional 2 characters by removing the parentheses from the regex and changing the $1 to $0. So, your formula would become: =TRIM(REGEXREPLACE(A1, ".", "$0 "))
    – Blindspots
    Sep 21, 2023 at 17:33

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