The filter() function looks through a source array, and filters it according to condition =FILTER(A:A,ISNUMBER(A:A)).

My source array is a rather long formula, so I end up repeating the same formula twice in the ISNUMBER() condition:

=FILTER(ARRAYFORMULA(1+(SORT(TRANSPOSE(FILTER($N9:9,ISNUMBER($N9:9),$N$3:$3="Skills [s]")),1,FALSE))*StackPenalty), ISNUMBER(ARRAYFORMULA(1+(SORT(TRANSPOSE(FILTER($N9:9,ISNUMBER($N9:9),$N$3:$3="Skills [s]")),1,FALSE))*StackPenalty)))

Is there any way I can write this shorter? Any way to reference the source array by some name? Index? Any way to use ISNUMBER() condition without passing the whole source array?

To recap: I need a way to reference the first argument of Filter() function in the second argument to that function, without repeating the whole argument explicitly.

Link to Spreadsheet. Sheet "Fitting Tool", cell L18 (change N9:9 in formula to N18:8), but this will be repeated throughout the L:L column.

  • Can you share a doc with us? Feb 18, 2013 at 6:57
  • Added link to OP
    – Slav
    Feb 18, 2013 at 11:22
  • Sorry, i only saw the comments from some people looking into this right now. I've reverted the spreadsheet and saved it under a different link (read OP). Thank you
    – Slav
    Feb 25, 2013 at 19:56
  • Is this the original sheet? Feb 25, 2013 at 20:59
  • Sheet Weapons doesn't exist..... Feb 25, 2013 at 21:11

2 Answers 2


I've been working on your file, even before the bounty period, and it as been a struggle. I wanted to give you the automation te ARRAYFORMULA can give in combination with a bit of Google Apps Script. In doing so, I wanted to understand the calculations a bit and thus I started with optimizing the first formula for column E:


For column H, I created to following formula:

=ARRAYFORMULA(IFERROR(VLOOKUP(G4:G30;Suits!A:AC;{MATCH(H2, suits!A1:AC1 ,0)}*SIGN(ROW(G4:G30));0),""))

For column I, I created the following script:

function skills(array1, array2, array3) {
  var array = new Array();

  for(i=0, len2=array2.length; i<len2; i++) {
    var prod = 1;
    for(j=0, len1=array1.length; j<len1; j++) {
      if("% " + array2[i][0] == array1[j][0]) {        
        prod *= array1[j][2] + 1;        
    var value;
    if(array3[i][0] == "") {
      value = "";
    } else {
      value = prod * array3[i][0];
  return array;

For column J, I created te following script:

function mods(array1, ModAttrb, ModHeader, ModStats, array5, array6) {
  var array = new Array(), aSecond = new Array(), aThird = new Array();

  // second calculation  
  for(i=0, len1=array1.length; i<len1; i++) {    
    var secondSum=0;    
    for(j=0, len2=ModAttrb.length; j<len2; j++) {      
      if(array1[i][0] == ModAttrb[j][0]) {        
        for(l=1, len4=ModStats[0].length; l<len4; l++) {
          if(ModStats[j][l] == 0 || ModStats[j][l] == "") {
            secondSum += 0;
          } else {
           secondSum += ModStats[j][l];

  // third calculation
  for(i=0, len1=array1.length; i<len1; i++) {
    var thirdSum=0;
    for(m=0, len5=array5.length; m<len5; m++) {
      if(array1[i][0] == array5[m][0]) {        
        thirdSum += parseInt(array5[m][3]);        
    if(thirdSum == 0) {
      thirdSum = 0;

  for (var i=0; i < aSecond.length; i++) {
    var result = 0;
    result += (array6[i] * 1 + parseInt(aSecond[i]) + parseInt(aThird[i]));
  return array;

Here, for the sake of time, I set the first calculation to be 1.

After that, time was running short. The Mult column is/was difficult to comprehense. We can work on it afterwards if you want?

See te example file I copied in te beginning: Fitting Tool

  • Thanks, you've done a lot of work, i will have to look into everything that you've done to understand it
    – Slav
    Mar 2, 2013 at 19:46

Plz all these two functions in your script editor and run and than =SHEETNAME() in any cell will return you the result

function SHEETNAME() {
  var ss = SpreadsheetApp.getActiveSpreadsheet();
  var s = ss.getActiveRange().getSheet();
  return s.getName();

function GETSHEETKEY() {
  //Browser.msgBox('Spreadsheet key: ' + SpreadsheetApp.getActiveSpreadsheet().getId());
  var s = SpreadsheetApp.getActiveSpreadsheet().getId()
  return s;

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.