2

Is there a way to create a feed of a friend's facebook wall updates such as status updates, shared links, uploaded photos...?

I have been using the following to subscribe to a facebook page:

https://www.facebook.com/feeds/page.php?id=<PAGE_ID>&format=rss20

But it doesn't work with profiles (using the profile numerical ID). I was able to generate what looks like a JSON of someone's photos using an access token generated via developer tools:

https://graph.facebook.com/<PROFILE_NAME>/photos?access_token=<ACCESS_TOKEN>

The resulting page looks like this:

{
   "data": [
      {
         "id": "<ID>",
         "from": {
            "name": "<NAME>",
            "id": "<ID>"
         },
         "name": "Thuggin",
         "picture": "<LINK_TO_.JPG>",
         "source": "<LINK_TO_.JPG>",
         "height": 540,
         "width": 720,
         "images": [
            {
               "height": 720,
               "width": 960,
               "source": "<LINK_TO_.JPG>"
            },

         ...

I also tried all suggestion found on this website. No good.

1 Answer 1

1

Facebook seems to be phasing out RSS feeds for information. Using the API (graph.facebook.com), is the most reasonable approach. You will need to know how to parse JSON via a programming language of your choice.

3
  • Seems fun. I'll do something this week and post it here as an answer. Thanks +1.
    – Alex
    May 8, 2013 at 21:56
  • where is your answer @Alex ?, am seems looking for your answer i need the same result you are asking Aug 29, 2013 at 11:09
  • @jothikannan I did not add an answer because the parser I made at the time didn't work properly and I didn't have the time to fix it and now I don't need this anymore. Feel free to try for yourself and add an answer, which might be useful for somebody else.
    – Alex
    Aug 29, 2013 at 11:43

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.