I want to get the email address of everyone I've had a conversation with over the last year [duplicate]

Question

This question already has an answer here:

• Get e-mail addresses from Gmail messages received 11 answers

I want to send a newsletter using MailChimp to everyone I've had an email conversation with over the past year.

What is the best way to export their email addresses?

I only want people I've gone back and forth with (I've sent them at least one email and they've sent me at least one email).

I'm on a Mac and can use Apple Mail if that helps.

Answer 1

Use this script to efficiently retrieve the addresses you want (given the time span) and remove duplicates:

Code

function getEmails() { 
  // http://stackoverflow.com/a/12029701/1536038  
  // get all messages      
  var eMails = GmailApp.getMessagesForThreads(
    GmailApp.search('after:2012/1/14 before:2013/8/15'))
      .reduce(function(a, b) {return a.concat(b);})
      .map(function(eMails) {
    return eMails.getFrom() 
  });

  // sort and filter for unique entries  
  var aEmails = eMails.sort().filter(function(el,j,a)
    {if(j==a.indexOf(el))return 1;return 0});  

  // create 2D-array
  var aUnique = new Array();  
  for(var k in aEmails) {
    aUnique.push([aEmails[k]]);
  }

  // add data to sheet
  SpreadsheetApp.getActiveSheet().getRange(1, 1, aUnique.length, 1)
    .setValues(aUnique);
} 

Answer 2

I think I wrote a script to do this in Google Apps Script

function processInbox() {
  // get all threads within the time range
  var threads =   GmailApp.search('after:2012/1/14 before:2014/8/15');
  var ss = SpreadsheetApp.getActiveSpreadsheet();
  // find all threads with more than one message     
  for (var i = 0; i < threads.length; i++) {
    var messages = threads[i].getMessages();
    // get all threads longer than 1
    if (messages.length > 1)
    {
      // get all participants in those threads and add them to a spreadsheet
      for (var j = 0; j< messages.length; j++){
        ss.appendRow([messages[j].getFrom()]);    
      }
    }
  };
};