According to Google Query documentation:

matches - A (preg) regular expression match. haystack matches needle is true if the regular expression in needle matches haystack. Examples: where country matches '.*ia' matches India and Nigeria, but not Indiana. Note that this is not a global search, so where country matches 'an' will not match 'Canada'.

I tried to use it in the formula =query('Общий список'!A3:V;"select * where B matches '/[A-Z]+/' "), but the query returns empty output.

Reference: https://developers.google.com/chart/interactive/docs/querylanguage#Where

  • Have you tried it without the forward slashes? Dec 12, 2013 at 21:17
  • yep, same result.
    – Gleb
    Dec 12, 2013 at 23:03
  • 1
    Why don't you share a doc with us?
    – Jacob Jan
    Dec 15, 2013 at 21:03
  • I just realised that the sheet title is cyrillic. You may need to add an extra range for the upper case Russian(?) characters. Dec 30, 2013 at 23:40

2 Answers 2


Note that this is not a global search...

This sentence explains what is going on: unlike the match in regexmatch, the matches clause of Query language requires the entire string to match the given regular expression. So, if you want to match strings where some part matches a regular expression re, the regular expression should be wrapped in .*:

select * where A matches '.*re.*'

Just a guess, but OP may want something like this:

=query(A:A, "Select A where A matches '.*/[A-Z]+/.*' ")  

to select from ColumnA only cells containing nothing but Latin alphabet upper case letters between two virgulas suspensiva (forward slashes) whether or not in the context of other characters.

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